-1,125x^2+9x=0

Solution for -1,125x^2+9x=0 equation:

-1.125x^2+9x=0

a = -1.125; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-1.125)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-1.125}=\frac{-18}{-2.25}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-1.125}=\frac{0}{-2.25}
=0
$